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x^2-5x+30=7x-10
We move all terms to the left:
x^2-5x+30-(7x-10)=0
We get rid of parentheses
x^2-5x-7x+10+30=0
We add all the numbers together, and all the variables
x^2-12x+40=0
a = 1; b = -12; c = +40;
Δ = b2-4ac
Δ = -122-4·1·40
Δ = -16
Delta is less than zero, so there is no solution for the equation
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